2(x+2)=-4x-3-8(x-6)

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Solution for 2(x+2)=-4x-3-8(x-6) equation: 



2(x+2)=-4x-3-8(x-6)

We move all terms to the left:

2(x+2)-(-4x-3-8(x-6))=0

We multiply parentheses

2x-(-4x-3-8(x-6))+4=0



We calculate terms in parentheses: -(-4x-3-8(x-6)), so:

-4x-3-8(x-6)

determiningTheFunctionDomain
-4x-8(x-6)-3

We multiply parentheses

-4x-8x+48-3

We add all the numbers together, and all the variables

-12x+45

Back to the equation:

-(-12x+45)



We get rid of parentheses

2x+12x-45+4=0

We add all the numbers together, and all the variables

14x-41=0

We move all terms containing x to the left, all other terms to the right

14x=41

x=41/14

x=2+13/14

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