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2(x+2)=3(2x-4)
We move all terms to the left:
2(x+2)-(3(2x-4))=0
We multiply parentheses
2x-(3(2x-4))+4=0
We calculate terms in parentheses: -(3(2x-4)), so:We get rid of parentheses
3(2x-4)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
2x-6x+12+4=0
We add all the numbers together, and all the variables
-4x+16=0
We move all terms containing x to the left, all other terms to the right
-4x=-16
x=-16/-4
x=+4
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