2(x+2)=3(x+1)

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Solution for 2(x+2)=3(x+1) equation: 



2(x+2)=3(x+1)

We move all terms to the left:

2(x+2)-(3(x+1))=0

We multiply parentheses

2x-(3(x+1))+4=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

2x-3x-3+4=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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