2(x+2)=3(x-7/8)

Solution for 2(x+2)=3(x-7/8) equation:

2(x+2)=3(x-7/8)

We move all terms to the left:

2(x+2)-(3(x-7/8))=0

We add all the numbers together, and all the variables

2(x+2)-(3(+x-7/8))=0

We multiply parentheses

2x-(3(+x-7/8))+4=0

We multiply all the terms by the denominator


2x*8))-(3(+x-7+4*8))=0

We add all the numbers together, and all the variables

2x*8))-(3(x+25))=0

We add all the numbers together, and all the variables

2x*8))-(3(x=0

Wy multiply elements

16x^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{32}=0$