2(x+2)=3+(x+5)

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Solution for 2(x+2)=3+(x+5) equation: 



2(x+2)=3+(x+5)

We move all terms to the left:

2(x+2)-(3+(x+5))=0

We multiply parentheses

2x-(3+(x+5))+4=0



We calculate terms in parentheses: -(3+(x+5)), so:

3+(x+5)

determiningTheFunctionDomain
(x+5)+3

We get rid of parentheses

x+5+3

We add all the numbers together, and all the variables

x+8

Back to the equation:

-(x+8)



We get rid of parentheses

2x-x-8+4=0

We add all the numbers together, and all the variables

x-4=0

We move all terms containing x to the left, all other terms to the right

x=4

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