2(x+2)=3x+8-(x+4)

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Solution for 2(x+2)=3x+8-(x+4) equation: 



2(x+2)=3x+8-(x+4)

We move all terms to the left:

2(x+2)-(3x+8-(x+4))=0

We multiply parentheses

2x-(3x+8-(x+4))+4=0



We calculate terms in parentheses: -(3x+8-(x+4)), so:

3x+8-(x+4)

determiningTheFunctionDomain
3x-(x+4)+8

We get rid of parentheses

3x-x-4+8

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We get rid of parentheses

2x-2x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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