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2(x+2)=4(2x+1)
We move all terms to the left:
2(x+2)-(4(2x+1))=0
We multiply parentheses
2x-(4(2x+1))+4=0
We calculate terms in parentheses: -(4(2x+1)), so:We get rid of parentheses
4(2x+1)
We multiply parentheses
8x+4
Back to the equation:
-(8x+4)
2x-8x-4+4=0
We add all the numbers together, and all the variables
-6x=0
x=0/-6
x=0
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