2(x+2)=4-(3-3x)=5

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Solution for 2(x+2)=4-(3-3x)=5 equation: 



2(x+2)=4-(3-3x)=5

We move all terms to the left:

2(x+2)-(4-(3-3x))=0

We add all the numbers together, and all the variables

2(x+2)-(4-(-3x+3))=0

We multiply parentheses

2x-(4-(-3x+3))+4=0



We calculate terms in parentheses: -(4-(-3x+3)), so:

4-(-3x+3)

determiningTheFunctionDomain
-(-3x+3)+4

We get rid of parentheses

3x-3+4

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We get rid of parentheses

2x-3x-1+4=0

We add all the numbers together, and all the variables

-1x+3=0

We move all terms containing x to the left, all other terms to the right

-x=-3

x=-3/-1

x=+3

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