2(x+2)=43-(x+4)

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Solution for 2(x+2)=43-(x+4) equation: 



2(x+2)=43-(x+4)

We move all terms to the left:

2(x+2)-(43-(x+4))=0

We multiply parentheses

2x-(43-(x+4))+4=0



We calculate terms in parentheses: -(43-(x+4)), so:

43-(x+4)

determiningTheFunctionDomain
-(x+4)+43

We get rid of parentheses

-x-4+43

We add all the numbers together, and all the variables

-1x+39

Back to the equation:

-(-1x+39)



We get rid of parentheses

2x+1x-39+4=0

We add all the numbers together, and all the variables

3x-35=0

We move all terms containing x to the left, all other terms to the right

3x=35

x=35/3

x=11+2/3

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