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2(x+2)=5x+1-(3x-3)
We move all terms to the left:
2(x+2)-(5x+1-(3x-3))=0
We multiply parentheses
2x-(5x+1-(3x-3))+4=0
We calculate terms in parentheses: -(5x+1-(3x-3)), so:We get rid of parentheses
5x+1-(3x-3)
determiningTheFunctionDomain 5x-(3x-3)+1
We get rid of parentheses
5x-3x+3+1
We add all the numbers together, and all the variables
2x+4
Back to the equation:
-(2x+4)
2x-2x-4+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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