2(x+2)=6(x+1)-(x-4)

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Solution for 2(x+2)=6(x+1)-(x-4) equation: 



2(x+2)=6(x+1)-(x-4)

We move all terms to the left:

2(x+2)-(6(x+1)-(x-4))=0

We multiply parentheses

2x-(6(x+1)-(x-4))+4=0



We calculate terms in parentheses: -(6(x+1)-(x-4)), so:

6(x+1)-(x-4)

We multiply parentheses

6x-(x-4)+6

We get rid of parentheses

6x-x+4+6

We add all the numbers together, and all the variables

5x+10

Back to the equation:

-(5x+10)



We get rid of parentheses

2x-5x-10+4=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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