2(x+2)=6(x-1)+18

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Solution for 2(x+2)=6(x-1)+18 equation:



2(x+2)=6(x-1)+18
We move all terms to the left:
2(x+2)-(6(x-1)+18)=0
We multiply parentheses
2x-(6(x-1)+18)+4=0
We calculate terms in parentheses: -(6(x-1)+18), so:
6(x-1)+18
We multiply parentheses
6x-6+18
We add all the numbers together, and all the variables
6x+12
Back to the equation:
-(6x+12)
We get rid of parentheses
2x-6x-12+4=0
We add all the numbers together, and all the variables
-4x-8=0
We move all terms containing x to the left, all other terms to the right
-4x=8
x=8/-4
x=-2

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