2(x+2)=8(x-2)-10

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Solution for 2(x+2)=8(x-2)-10 equation: 



2(x+2)=8(x-2)-10

We move all terms to the left:

2(x+2)-(8(x-2)-10)=0

We multiply parentheses

2x-(8(x-2)-10)+4=0



We calculate terms in parentheses: -(8(x-2)-10), so:

8(x-2)-10

We multiply parentheses

8x-16-10

We add all the numbers together, and all the variables

8x-26

Back to the equation:

-(8x-26)



We get rid of parentheses

2x-8x+26+4=0

We add all the numbers together, and all the variables

-6x+30=0

We move all terms containing x to the left, all other terms to the right

-6x=-30

x=-30/-6

x=+5

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