2(x+2,2)+4x=3(x+2)-1,6

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Solution for 2(x+2,2)+4x=3(x+2)-1,6 equation: 



2(x+2.2)+4x=3(x+2)-1.6

We move all terms to the left:

2(x+2.2)+4x-(3(x+2)-1.6)=0

We add all the numbers together, and all the variables

4x+2(x+2.2)-(3(x+2)-1.6)=0

We multiply parentheses

4x+2x-(3(x+2)-1.6)+4.4=0



We calculate terms in parentheses: -(3(x+2)-1.6), so:

3(x+2)-1.6

We multiply parentheses

3x+6-1.6

We add all the numbers together, and all the variables

3x+4.4

Back to the equation:

-(3x+4.4)



We add all the numbers together, and all the variables

6x-(3x+4.4)+4.4=0

We get rid of parentheses

6x-3x-4.4+4.4=0

We add all the numbers together, and all the variables

3x=0

x=0/3

x=0

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