2(x+3)(x+3)+4=0

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Solution for 2(x+3)(x+3)+4=0 equation:



2(x+3)(x+3)+4=0
We multiply parentheses ..
2(+x^2+3x+3x+9)+4=0
We multiply parentheses
2x^2+6x+6x+18+4=0
We add all the numbers together, and all the variables
2x^2+12x+22=0
a = 2; b = 12; c = +22;
Δ = b2-4ac
Δ = 122-4·2·22
Δ = -32
Delta is less than zero, so there is no solution for the equation

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