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2(x+3)(x-11)=0
We multiply parentheses ..
2(+x^2-11x+3x-33)=0
We multiply parentheses
2x^2-22x+6x-66=0
We add all the numbers together, and all the variables
2x^2-16x-66=0
a = 2; b = -16; c = -66;
Δ = b2-4ac
Δ = -162-4·2·(-66)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-28}{2*2}=\frac{-12}{4} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+28}{2*2}=\frac{44}{4} =11 $
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