2(x+3)*3=(7x-2)*2

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Solution for 2(x+3)*3=(7x-2)*2 equation: 



2(x+3)*3=(7x-2)*2

We move all terms to the left:

2(x+3)*3-((7x-2)*2)=0

We multiply parentheses

6x-((7x-2)*2)+18=0



We calculate terms in parentheses: -((7x-2)*2), so:

(7x-2)*2

We multiply parentheses

14x-4

Back to the equation:

-(14x-4)



We get rid of parentheses

6x-14x+4+18=0

We add all the numbers together, and all the variables

-8x+22=0

We move all terms containing x to the left, all other terms to the right

-8x=-22

x=-22/-8

x=2+3/4

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