2(x+3)+12=6-2(3x-5)

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Solution for 2(x+3)+12=6-2(3x-5) equation: 



2(x+3)+12=6-2(3x-5)

We move all terms to the left:

2(x+3)+12-(6-2(3x-5))=0

We multiply parentheses

2x-(6-2(3x-5))+6+12=0



We calculate terms in parentheses: -(6-2(3x-5)), so:

6-2(3x-5)

determiningTheFunctionDomain
-2(3x-5)+6

We multiply parentheses

-6x+10+6

We add all the numbers together, and all the variables

-6x+16

Back to the equation:

-(-6x+16)



We add all the numbers together, and all the variables

2x-(-6x+16)+18=0

We get rid of parentheses

2x+6x-16+18=0

We add all the numbers together, and all the variables

8x+2=0

We move all terms containing x to the left, all other terms to the right

8x=-2

x=-2/8

x=-1/4

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