2(x+3)+1=3(x+2)

Solution for 2(x+3)+1=3(x+2) equation:

2(x+3)+1=3(x+2)

We move all terms to the left:

2(x+3)+1-(3(x+2))=0

We multiply parentheses

2x-(3(x+2))+6+1=0


We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)


We add all the numbers together, and all the variables

2x-(3x+6)+7=0

We get rid of parentheses

2x-3x-6+7=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1