2(x+3)+2(x+1)=6(x+1)-1

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Solution for 2(x+3)+2(x+1)=6(x+1)-1 equation: 



2(x+3)+2(x+1)=6(x+1)-1

We move all terms to the left:

2(x+3)+2(x+1)-(6(x+1)-1)=0

We multiply parentheses

2x+2x-(6(x+1)-1)+6+2=0



We calculate terms in parentheses: -(6(x+1)-1), so:

6(x+1)-1

We multiply parentheses

6x+6-1

We add all the numbers together, and all the variables

6x+5

Back to the equation:

-(6x+5)



We add all the numbers together, and all the variables

4x-(6x+5)+8=0

We get rid of parentheses

4x-6x-5+8=0

We add all the numbers together, and all the variables

-2x+3=0

We move all terms containing x to the left, all other terms to the right

-2x=-3

x=-3/-2

x=1+1/2

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