2(x+3)+2x=3(x-4)

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Solution for 2(x+3)+2x=3(x-4) equation:



2(x+3)+2x=3(x-4)
We move all terms to the left:
2(x+3)+2x-(3(x-4))=0
We add all the numbers together, and all the variables
2x+2(x+3)-(3(x-4))=0
We multiply parentheses
2x+2x-(3(x-4))+6=0
We calculate terms in parentheses: -(3(x-4)), so:
3(x-4)
We multiply parentheses
3x-12
Back to the equation:
-(3x-12)
We add all the numbers together, and all the variables
4x-(3x-12)+6=0
We get rid of parentheses
4x-3x+12+6=0
We add all the numbers together, and all the variables
x+18=0
We move all terms containing x to the left, all other terms to the right
x=-18

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