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2(x+3)+2x=x-3(x-4)
We move all terms to the left:
2(x+3)+2x-(x-3(x-4))=0
We add all the numbers together, and all the variables
2x+2(x+3)-(x-3(x-4))=0
We multiply parentheses
2x+2x-(x-3(x-4))+6=0
We calculate terms in parentheses: -(x-3(x-4)), so:We add all the numbers together, and all the variables
x-3(x-4)
We multiply parentheses
x-3x+12
We add all the numbers together, and all the variables
-2x+12
Back to the equation:
-(-2x+12)
4x-(-2x+12)+6=0
We get rid of parentheses
4x+2x-12+6=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1
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