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2(x+3)+3(2x-4)=4(11-3x)
We move all terms to the left:
2(x+3)+3(2x-4)-(4(11-3x))=0
We add all the numbers together, and all the variables
2(x+3)+3(2x-4)-(4(-3x+11))=0
We multiply parentheses
2x+6x-(4(-3x+11))+6-12=0
We calculate terms in parentheses: -(4(-3x+11)), so:We add all the numbers together, and all the variables
4(-3x+11)
We multiply parentheses
-12x+44
Back to the equation:
-(-12x+44)
8x-(-12x+44)-6=0
We get rid of parentheses
8x+12x-44-6=0
We add all the numbers together, and all the variables
20x-50=0
We move all terms containing x to the left, all other terms to the right
20x=50
x=50/20
x=2+1/2
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