2(x+3)+3(x+1)=4(2x-3)

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Solution for 2(x+3)+3(x+1)=4(2x-3) equation: 



2(x+3)+3(x+1)=4(2x-3)

We move all terms to the left:

2(x+3)+3(x+1)-(4(2x-3))=0

We multiply parentheses

2x+3x-(4(2x-3))+6+3=0



We calculate terms in parentheses: -(4(2x-3)), so:

4(2x-3)

We multiply parentheses

8x-12

Back to the equation:

-(8x-12)



We add all the numbers together, and all the variables

5x-(8x-12)+9=0

We get rid of parentheses

5x-8x+12+9=0

We add all the numbers together, and all the variables

-3x+21=0

We move all terms containing x to the left, all other terms to the right

-3x=-21

x=-21/-3

x=+7

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