2(x+3)+3(x+1)=4(x+2)+5(x+1)

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Solution for 2(x+3)+3(x+1)=4(x+2)+5(x+1) equation: 



2(x+3)+3(x+1)=4(x+2)+5(x+1)

We move all terms to the left:

2(x+3)+3(x+1)-(4(x+2)+5(x+1))=0

We multiply parentheses

2x+3x-(4(x+2)+5(x+1))+6+3=0



We calculate terms in parentheses: -(4(x+2)+5(x+1)), so:

4(x+2)+5(x+1)

We multiply parentheses

4x+5x+8+5

We add all the numbers together, and all the variables

9x+13

Back to the equation:

-(9x+13)



We add all the numbers together, and all the variables

5x-(9x+13)+9=0

We get rid of parentheses

5x-9x-13+9=0

We add all the numbers together, and all the variables

-4x-4=0

We move all terms containing x to the left, all other terms to the right

-4x=4

x=4/-4

x=-1

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