2(x+3)+3=3(x+4)+1

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Solution for 2(x+3)+3=3(x+4)+1 equation: 



2(x+3)+3=3(x+4)+1

We move all terms to the left:

2(x+3)+3-(3(x+4)+1)=0

We multiply parentheses

2x-(3(x+4)+1)+6+3=0



We calculate terms in parentheses: -(3(x+4)+1), so:

3(x+4)+1

We multiply parentheses

3x+12+1

We add all the numbers together, and all the variables

3x+13

Back to the equation:

-(3x+13)



We add all the numbers together, and all the variables

2x-(3x+13)+9=0

We get rid of parentheses

2x-3x-13+9=0

We add all the numbers together, and all the variables

-1x-4=0

We move all terms containing x to the left, all other terms to the right

-x=4

x=4/-1

x=-4

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