2(x+3)+3x+4=2(x+20)-x-6

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Solution for 2(x+3)+3x+4=2(x+20)-x-6 equation: 



2(x+3)+3x+4=2(x+20)-x-6

We move all terms to the left:

2(x+3)+3x+4-(2(x+20)-x-6)=0

We add all the numbers together, and all the variables

3x+2(x+3)-(2(x+20)-x-6)+4=0

We multiply parentheses

3x+2x-(2(x+20)-x-6)+6+4=0



We calculate terms in parentheses: -(2(x+20)-x-6), so:

2(x+20)-x-6

We add all the numbers together, and all the variables

-1x+2(x+20)-6

We multiply parentheses

-1x+2x+40-6

We add all the numbers together, and all the variables

x+34

Back to the equation:

-(x+34)



We add all the numbers together, and all the variables

5x-(x+34)+10=0

We get rid of parentheses

5x-x-34+10=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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