2(x+3)+4(x+1)=22

Solution for 2(x+3)+4(x+1)=22 equation:

Simplifying
2(x + 3) + 4(x + 1) = 22

Reorder the terms:
2(3 + x) + 4(x + 1) = 22
(3 * 2 + x * 2) + 4(x + 1) = 22
(6 + 2x) + 4(x + 1) = 22

Reorder the terms:
6 + 2x + 4(1 + x) = 22
6 + 2x + (1 * 4 + x * 4) = 22
6 + 2x + (4 + 4x) = 22

Reorder the terms:
6 + 4 + 2x + 4x = 22

Combine like terms: 6 + 4 = 10
10 + 2x + 4x = 22

Combine like terms: 2x + 4x = 6x
10 + 6x = 22

Solving
10 + 6x = 22

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + 6x = 22 + -10

Combine like terms: 10 + -10 = 0
0 + 6x = 22 + -10
6x = 22 + -10

Combine like terms: 22 + -10 = 12
6x = 12

Divide each side by '6'.
x = 2

Simplifying
x = 2