2(x+3)+4(x+7)=4(x-7)+12(x+3)+6

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Solution for 2(x+3)+4(x+7)=4(x-7)+12(x+3)+6 equation: 



2(x+3)+4(x+7)=4(x-7)+12(x+3)+6

We move all terms to the left:

2(x+3)+4(x+7)-(4(x-7)+12(x+3)+6)=0

We multiply parentheses

2x+4x-(4(x-7)+12(x+3)+6)+6+28=0



We calculate terms in parentheses: -(4(x-7)+12(x+3)+6), so:

4(x-7)+12(x+3)+6

We multiply parentheses

4x+12x-28+36+6

We add all the numbers together, and all the variables

16x+14

Back to the equation:

-(16x+14)



We add all the numbers together, and all the variables

6x-(16x+14)+34=0

We get rid of parentheses

6x-16x-14+34=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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