2(x+3)+4x=20

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Solution for 2(x+3)+4x=20 equation: 



2(x+3)+4x=20

We move all terms to the left:

2(x+3)+4x-(20)=0

We add all the numbers together, and all the variables

4x+2(x+3)-20=0

We multiply parentheses

4x+2x+6-20=0

We add all the numbers together, and all the variables

6x-14=0

We move all terms containing x to the left, all other terms to the right

6x=14

x=14/6

x=2+1/3

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