2(x+3)+5=3(x+1)-8

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Solution for 2(x+3)+5=3(x+1)-8 equation: 



2(x+3)+5=3(x+1)-8

We move all terms to the left:

2(x+3)+5-(3(x+1)-8)=0

We multiply parentheses

2x-(3(x+1)-8)+6+5=0



We calculate terms in parentheses: -(3(x+1)-8), so:

3(x+1)-8

We multiply parentheses

3x+3-8

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We add all the numbers together, and all the variables

2x-(3x-5)+11=0

We get rid of parentheses

2x-3x+5+11=0

We add all the numbers together, and all the variables

-1x+16=0

We move all terms containing x to the left, all other terms to the right

-x=-16

x=-16/-1

x=+16

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