2(x+3)+5x=3(2x+1)

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Solution for 2(x+3)+5x=3(2x+1) equation: 



2(x+3)+5x=3(2x+1)

We move all terms to the left:

2(x+3)+5x-(3(2x+1))=0

We add all the numbers together, and all the variables

5x+2(x+3)-(3(2x+1))=0

We multiply parentheses

5x+2x-(3(2x+1))+6=0



We calculate terms in parentheses: -(3(2x+1)), so:

3(2x+1)

We multiply parentheses

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

7x-(6x+3)+6=0

We get rid of parentheses

7x-6x-3+6=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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