2(x+3)+7x=3(x-2)-9

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Solution for 2(x+3)+7x=3(x-2)-9 equation: 



2(x+3)+7x=3(x-2)-9

We move all terms to the left:

2(x+3)+7x-(3(x-2)-9)=0

We add all the numbers together, and all the variables

7x+2(x+3)-(3(x-2)-9)=0

We multiply parentheses

7x+2x-(3(x-2)-9)+6=0



We calculate terms in parentheses: -(3(x-2)-9), so:

3(x-2)-9

We multiply parentheses

3x-6-9

We add all the numbers together, and all the variables

3x-15

Back to the equation:

-(3x-15)



We add all the numbers together, and all the variables

9x-(3x-15)+6=0

We get rid of parentheses

9x-3x+15+6=0

We add all the numbers together, and all the variables

6x+21=0

We move all terms containing x to the left, all other terms to the right

6x=-21

x=-21/6

x=-3+1/2

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