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2(x+3)+x=3(x+1)
We move all terms to the left:
2(x+3)+x-(3(x+1))=0
We add all the numbers together, and all the variables
x+2(x+3)-(3(x+1))=0
We multiply parentheses
x+2x-(3(x+1))+6=0
We calculate terms in parentheses: -(3(x+1)), so:We add all the numbers together, and all the variables
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
3x-(3x+3)+6=0
We get rid of parentheses
3x-3x-3+6=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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