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2(x+3)-3(x+2)=5-4(x+1)
We move all terms to the left:
2(x+3)-3(x+2)-(5-4(x+1))=0
We multiply parentheses
2x-3x-(5-4(x+1))+6-6=0
We calculate terms in parentheses: -(5-4(x+1)), so:We add all the numbers together, and all the variables
5-4(x+1)
determiningTheFunctionDomain -4(x+1)+5
We multiply parentheses
-4x-4+5
We add all the numbers together, and all the variables
-4x+1
Back to the equation:
-(-4x+1)
-1x-(-4x+1)=0
We get rid of parentheses
-1x+4x-1=0
We add all the numbers together, and all the variables
3x-1=0
We move all terms containing x to the left, all other terms to the right
3x=1
x=1/3
x=1/3
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