2(x+3)-3(x-2)=x+2-(x-6)

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Solution for 2(x+3)-3(x-2)=x+2-(x-6) equation: 



2(x+3)-3(x-2)=x+2-(x-6)

We move all terms to the left:

2(x+3)-3(x-2)-(x+2-(x-6))=0

We multiply parentheses

2x-3x-(x+2-(x-6))+6+6=0



We calculate terms in parentheses: -(x+2-(x-6)), so:

x+2-(x-6)

determiningTheFunctionDomain
x-(x-6)+2

We get rid of parentheses

x-x+6+2

We add all the numbers together, and all the variables

8

Back to the equation:

-(8)



We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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