2(x+3)-4(x+5)+13=19-3(x-1)

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Solution for 2(x+3)-4(x+5)+13=19-3(x-1) equation: 



2(x+3)-4(x+5)+13=19-3(x-1)

We move all terms to the left:

2(x+3)-4(x+5)+13-(19-3(x-1))=0

We multiply parentheses

2x-4x-(19-3(x-1))+6-20+13=0



We calculate terms in parentheses: -(19-3(x-1)), so:

19-3(x-1)

determiningTheFunctionDomain
-3(x-1)+19

We multiply parentheses

-3x+3+19

We add all the numbers together, and all the variables

-3x+22

Back to the equation:

-(-3x+22)



We add all the numbers together, and all the variables

-2x-(-3x+22)-1=0

We get rid of parentheses

-2x+3x-22-1=0

We add all the numbers together, and all the variables

x-23=0

We move all terms containing x to the left, all other terms to the right

x=23

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