2(x+3)-4=8(x/2+1)

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Solution for 2(x+3)-4=8(x/2+1) equation: 



2(x+3)-4=8(x/2+1)

We move all terms to the left:

2(x+3)-4-(8(x/2+1))=0

We multiply parentheses

2x-(8(x/2+1))+6-4=0

We multiply all the terms by the denominator


2x*2+1))-(8(x+6*2+1))-4*2+1))=0

We add all the numbers together, and all the variables

2x*2+1))-(8(x+13))-4*2+1))=0

We add all the numbers together, and all the variables

2x*2+1))-(8(x=0

Wy multiply elements

4x+1))-(8(x=0

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