2(x+3)-5=6(x+1)-3

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Solution for 2(x+3)-5=6(x+1)-3 equation: 



2(x+3)-5=6(x+1)-3

We move all terms to the left:

2(x+3)-5-(6(x+1)-3)=0

We multiply parentheses

2x-(6(x+1)-3)+6-5=0



We calculate terms in parentheses: -(6(x+1)-3), so:

6(x+1)-3

We multiply parentheses

6x+6-3

We add all the numbers together, and all the variables

6x+3

Back to the equation:

-(6x+3)



We add all the numbers together, and all the variables

2x-(6x+3)+1=0

We get rid of parentheses

2x-6x-3+1=0

We add all the numbers together, and all the variables

-4x-2=0

We move all terms containing x to the left, all other terms to the right

-4x=2

x=2/-4

x=-1/2

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