2(x+3)-5=7-4(2x-5)

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Solution for 2(x+3)-5=7-4(2x-5) equation: 



2(x+3)-5=7-4(2x-5)

We move all terms to the left:

2(x+3)-5-(7-4(2x-5))=0

We multiply parentheses

2x-(7-4(2x-5))+6-5=0



We calculate terms in parentheses: -(7-4(2x-5)), so:

7-4(2x-5)

determiningTheFunctionDomain
-4(2x-5)+7

We multiply parentheses

-8x+20+7

We add all the numbers together, and all the variables

-8x+27

Back to the equation:

-(-8x+27)



We add all the numbers together, and all the variables

2x-(-8x+27)+1=0

We get rid of parentheses

2x+8x-27+1=0

We add all the numbers together, and all the variables

10x-26=0

We move all terms containing x to the left, all other terms to the right

10x=26

x=26/10

x=2+3/5

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