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2(x+3)-5x=(3x+5)-8
We move all terms to the left:
2(x+3)-5x-((3x+5)-8)=0
We add all the numbers together, and all the variables
-5x+2(x+3)-((3x+5)-8)=0
We multiply parentheses
-5x+2x-((3x+5)-8)+6=0
We calculate terms in parentheses: -((3x+5)-8), so:We add all the numbers together, and all the variables
(3x+5)-8
We get rid of parentheses
3x+5-8
We add all the numbers together, and all the variables
3x-3
Back to the equation:
-(3x-3)
-3x-(3x-3)+6=0
We get rid of parentheses
-3x-3x+3+6=0
We add all the numbers together, and all the variables
-6x+9=0
We move all terms containing x to the left, all other terms to the right
-6x=-9
x=-9/-6
x=1+1/2
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