2(x+3)-6(x-4)=-38

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Solution for 2(x+3)-6(x-4)=-38 equation: 



2(x+3)-6(x-4)=-38

We move all terms to the left:

2(x+3)-6(x-4)-(-38)=0

We add all the numbers together, and all the variables

2(x+3)-6(x-4)+38=0

We multiply parentheses

2x-6x+6+24+38=0

We add all the numbers together, and all the variables

-4x+68=0

We move all terms containing x to the left, all other terms to the right

-4x=-68

x=-68/-4

x=+17

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