2(x+3)-7(3x-6)=16

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Solution for 2(x+3)-7(3x-6)=16 equation: 



2(x+3)-7(3x-6)=16

We move all terms to the left:

2(x+3)-7(3x-6)-(16)=0

We multiply parentheses

2x-21x+6+42-16=0

We add all the numbers together, and all the variables

-19x+32=0

We move all terms containing x to the left, all other terms to the right

-19x=-32

x=-32/-19

x=1+13/19

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