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2(x+3)-7(3x-6)=16
We move all terms to the left:
2(x+3)-7(3x-6)-(16)=0
We multiply parentheses
2x-21x+6+42-16=0
We add all the numbers together, and all the variables
-19x+32=0
We move all terms containing x to the left, all other terms to the right
-19x=-32
x=-32/-19
x=1+13/19
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