2(x+3)-7x=18+5(x+2x)

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Solution for 2(x+3)-7x=18+5(x+2x) equation: 



2(x+3)-7x=18+5(x+2x)

We move all terms to the left:

2(x+3)-7x-(18+5(x+2x))=0

We add all the numbers together, and all the variables

2(x+3)-7x-(18+5(+3x))=0

We add all the numbers together, and all the variables

-7x+2(x+3)-(18+5(+3x))=0

We multiply parentheses

-7x+2x-(18+5(+3x))+6=0



We calculate terms in parentheses: -(18+5(+3x)), so:

18+5(+3x)

determiningTheFunctionDomain
5(+3x)+18

We multiply parentheses

15x+18

Back to the equation:

-(15x+18)



We add all the numbers together, and all the variables

-5x-(15x+18)+6=0

We get rid of parentheses

-5x-15x-18+6=0

We add all the numbers together, and all the variables

-20x-12=0

We move all terms containing x to the left, all other terms to the right

-20x=12

x=12/-20

x=-3/5

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