2(x+3)-7x=18+5(x+4)

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Solution for 2(x+3)-7x=18+5(x+4) equation: 



2(x+3)-7x=18+5(x+4)

We move all terms to the left:

2(x+3)-7x-(18+5(x+4))=0

We add all the numbers together, and all the variables

-7x+2(x+3)-(18+5(x+4))=0

We multiply parentheses

-7x+2x-(18+5(x+4))+6=0



We calculate terms in parentheses: -(18+5(x+4)), so:

18+5(x+4)

determiningTheFunctionDomain
5(x+4)+18

We multiply parentheses

5x+20+18

We add all the numbers together, and all the variables

5x+38

Back to the equation:

-(5x+38)



We add all the numbers together, and all the variables

-5x-(5x+38)+6=0

We get rid of parentheses

-5x-5x-38+6=0

We add all the numbers together, and all the variables

-10x-32=0

We move all terms containing x to the left, all other terms to the right

-10x=32

x=32/-10

x=-3+1/5

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