2(x+3)-7x=23-5(x+3x)

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Solution for 2(x+3)-7x=23-5(x+3x) equation:



2(x+3)-7x=23-5(x+3x)
We move all terms to the left:
2(x+3)-7x-(23-5(x+3x))=0
We add all the numbers together, and all the variables
2(x+3)-7x-(23-5(+4x))=0
We add all the numbers together, and all the variables
-7x+2(x+3)-(23-5(+4x))=0
We multiply parentheses
-7x+2x-(23-5(+4x))+6=0
We calculate terms in parentheses: -(23-5(+4x)), so:
23-5(+4x)
determiningTheFunctionDomain -5(+4x)+23
We multiply parentheses
-20x+23
Back to the equation:
-(-20x+23)
We add all the numbers together, and all the variables
-5x-(-20x+23)+6=0
We get rid of parentheses
-5x+20x-23+6=0
We add all the numbers together, and all the variables
15x-17=0
We move all terms containing x to the left, all other terms to the right
15x=17
x=17/15
x=1+2/15

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