2(x+3)-x+8=6(x-5)+2

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Solution for 2(x+3)-x+8=6(x-5)+2 equation: 



2(x+3)-x+8=6(x-5)+2

We move all terms to the left:

2(x+3)-x+8-(6(x-5)+2)=0

We add all the numbers together, and all the variables

-1x+2(x+3)-(6(x-5)+2)+8=0

We multiply parentheses

-1x+2x-(6(x-5)+2)+6+8=0



We calculate terms in parentheses: -(6(x-5)+2), so:

6(x-5)+2

We multiply parentheses

6x-30+2

We add all the numbers together, and all the variables

6x-28

Back to the equation:

-(6x-28)



We add all the numbers together, and all the variables

x-(6x-28)+14=0

We get rid of parentheses

x-6x+28+14=0

We add all the numbers together, and all the variables

-5x+42=0

We move all terms containing x to the left, all other terms to the right

-5x=-42

x=-42/-5

x=8+2/5

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