2(x+3)=(4x-1)+6

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Solution for 2(x+3)=(4x-1)+6 equation: 



2(x+3)=(4x-1)+6

We move all terms to the left:

2(x+3)-((4x-1)+6)=0

We multiply parentheses

2x-((4x-1)+6)+6=0



We calculate terms in parentheses: -((4x-1)+6), so:

(4x-1)+6

We get rid of parentheses

4x-1+6

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We get rid of parentheses

2x-4x-5+6=0

We add all the numbers together, and all the variables

-2x+1=0

We move all terms containing x to the left, all other terms to the right

-2x=-1

x=-1/-2

x=1/2

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