2(x+3)=(6-x)+7

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Solution for 2(x+3)=(6-x)+7 equation:



2(x+3)=(6-x)+7
We move all terms to the left:
2(x+3)-((6-x)+7)=0
We add all the numbers together, and all the variables
2(x+3)-((-1x+6)+7)=0
We multiply parentheses
2x-((-1x+6)+7)+6=0
We calculate terms in parentheses: -((-1x+6)+7), so:
(-1x+6)+7
We get rid of parentheses
-1x+6+7
We add all the numbers together, and all the variables
-1x+13
Back to the equation:
-(-1x+13)
We get rid of parentheses
2x+1x-13+6=0
We add all the numbers together, and all the variables
3x-7=0
We move all terms containing x to the left, all other terms to the right
3x=7
x=7/3
x=2+1/3

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