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2(x+3)=+-4(2x-1)+2
We move all terms to the left:
2(x+3)-(+-4(2x-1)+2)=0
We use the square of the difference formula
2(x+3)-(-4(2x-1)+2)=0
We multiply parentheses
2x-(-4(2x-1)+2)+6=0
We calculate terms in parentheses: -(-4(2x-1)+2), so:We get rid of parentheses
-4(2x-1)+2
We multiply parentheses
-8x+4+2
We add all the numbers together, and all the variables
-8x+6
Back to the equation:
-(-8x+6)
2x+8x-6+6=0
We add all the numbers together, and all the variables
10x=0
x=0/10
x=0
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